Unit 7: Exponential and General Functions

Topic 1

Exponential Growth and Decay

Exponential functions model situations where a quantity changes by a constant percentage rate over equal time intervals. They have the general form:
y=abx,y = a \, b^x,
where:
  • aa is the initial value (when x=0x = 0),
  • bb is the growth or decay factor,
  • xx is the time or independent variable.
{b>1Exponential Growth0<b<1Exponential Decay\begin{cases} b > 1 & \text{Exponential Growth} \\ 0 < b < 1 & \text{Exponential Decay} \end{cases}
Each increase of 1 unit in xx multiplies the value of yy by bb, not adds to it. This is the key difference from linear functions, which change by a constant amount.
The percentage rate of change can be written as:
b=1+rfor growth,b=1rfor decay,b = 1 + r \quad \text{for growth}, \qquad b = 1 - r \quad \text{for decay},
where rr is the rate expressed as a decimal.
Exponential Growth Example Population, compound interest, or bacteria doubling over time follow growth patterns.
P(t)=P0(1+r)tP(t) = P_0 (1 + r)^t
Exponential Decay Example Radioactive decay or depreciation of value follow decay patterns.
A(t)=A0(1r)tA(t) = A_0 (1 - r)^t

Core Skills

  • Identify aa, bb, and the growth/decay rate rr.
  • Distinguish between linear (additive) and exponential (multiplicative) change.
  • Write exponential models from verbal descriptions or data.
  • Evaluate exponential expressions for given time intervals.
  • Interpret real-world meanings of constants aa, bb, and rr.

Example 1: Identifying Growth or Decay

Determine whether each function represents growth or decay:
(a) y=200(1.05)x,(b) y=500(0.92)x.\text{(a) } y = 200(1.05)^x, \quad \text{(b) } y = 500(0.92)^x.
(a) b=1.05>1b = 1.05 > 1 → Growth (5% increase per unit). (b) b=0.92<1b = 0.92 < 1 → Decay (8% decrease per unit). Answer: (a) Growth; (b) Decay.

Example 2: Writing an Exponential Model

A population of 1000 bacteria doubles every 4 hours.
P(t)=1000(2)t/4.P(t) = 1000(2)^{t/4}.
Each 4-hour period multiplies the amount by 2. Interpretation: a=1000a = 1000, doubling time = 4 hours.

Example 3: Finding the Growth Rate

An investment grows according to A=500(1.06)t.A = 500(1.06)^t. Here r=0.06,r = 0.06, so growth rate = 6% per time unit. After 5 years:
A=500(1.06)5=500(1.3382)=669.1.A = 500(1.06)^5 = 500(1.3382) = 669.1.
A=$669.10\boxed{A = \$669.10}

Example 4: Exponential Decay Model

A car’s value is modeled by V=30,000(0.85)t,V = 30{,}000(0.85)^t, where tt is years after purchase. Each year, it retains 85% of its previous value → 15% loss annually. After 3 years:
V=30,000(0.85)3=30,000(0.614125)=18,423.75.V = 30{,}000(0.85)^3 = 30{,}000(0.614125) = 18{,}423.75.
V=$18,423.75\boxed{V = \$18{,}423.75}

Example 5: Comparing Two Models

Compare y=100(1.03)xy = 100(1.03)^x and y=100(0.97)x.y = 100(0.97)^x. The first model grows 3% each period; the second decays 3%. If x=10x = 10:
y1=100(1.03)10=134.4,y2=100(0.97)10=73.7.y_1 = 100(1.03)^{10} = 134.4, \quad y_2 = 100(0.97)^{10} = 73.7.
Interpretation: Growth doubles faster than decay reduces.

Example 6: Graph Behavior

A growth curve (b>1b > 1) rises rapidly to the right, while a decay curve (0<b<10 < b < 1) decreases toward 0. Key features:
  • Both pass through (0,a)(0, a).
  • Growth curves rise to the right.
  • Decay curves fall to the right.
  • The x-axis (y=0y = 0) is a horizontal asymptote.

Key Takeaways

  • Exponential growth multiplies by a constant factor b>1b > 1.
  • Exponential decay multiplies by 0<b<10 < b < 1.
  • Rate rr links to bb through b=1±r.b = 1 \pm r.
  • Graphs approach but never reach 0 (asymptote at y=0y = 0).
  • Recognizing bb and interpreting context are key SAT skills.